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The angle between the vectors veca = 3 ...

The angle between the vectors `veca = 3 hati - 4 haj and vecb =- 2 hati + 3 hatk ` is

A

`cos ^(-1) [-(6)/(5sqrt(13))]`

B

`cos ^(-1)[-(1)/(4)]`

C

`cos ^(-1)[-(1)/(2)]`

D

`cos ^(-1) [+(6)/(5sqrt(13))]`

Text Solution

Verified by Experts

The correct Answer is:
A
`vecA . B = AB cos theta `
` cos theta = (vecA . vecB)/(|vecA||vecB|)=(-6)/(5sqrt(13))`
` therefore theta = cos ^(-1) [ (-6)/(5sqrt(13))]`
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