A copper wire of resistance `R` is cut into ten parts of equal length. Two pieces each are joined in series and then five such combination are joined in parallel. The new combination will have resistance

Answer

D

Explanation

Each cut part has Res `(R )/(10 ) `
Two are joined in series ` therefore (2R )/(10) =(R )/(5 )`
Now therefore are 5 parallel branches each having (R )/(5 )
` therefore R _(net ) =(R //5 ) /(n ) =(R )/(25 )`