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CH(3)-C -= N +underset("(excess)")(H(2)O...

`CH_(3)-C -= N +underset("(excess)")(H_(2)O) overset(H^(+))to A underset(Delta)overset(NaOH+CaO)to B`
B is ?

A

`CH_(3)-overset(O)overset(||)C-NH_(2)`

B

`CH_(3)-overset(O)overset(|)C-OH`

C

`CH_(3)-overset(O)overset(|)C-O"Na"`

D

`CH_(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`CH_(3)-C-=N + H_(2)O overset(H^(o+))to underset(+NH_(3))(CH_(3)-overset(O)overset(||)C-OH) underset(Delta)overset("soda lime")to CH_(4)+CO_(2)`
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