[" If point "(x,y)" is equidistant from the "],[[a-b,a+b)" then prove "bx=ay]]

If the point (x,y) is equidistant from (7,1) and (3,5) , then

If the points (x,y) is equidistant from (2,-1) and (-3,4) then prove that y = x + 2.

If the point (x,y) is equidistant from the points (a+b,b-a) and (a-b,a+b) prove that bx=ay

If the point (x,y) is equidistant from the points (a-b,a+b) and (-a-b,a+b) . Prove that x+b=0

If the point (x, y) is equidistant from the points (a+b, b-a) and (a-b, a+b), then prove that bx=ay.

If a point (x,y) is equidistant from the Q(9,8) and S(17,8) ,then (i) x+y=13 (ii) x-13=0 (iii) y-13=0 (iv)x-y=13

If a point (x,y) is equidistant from the points A(9,8) and B(17,8), then the relation between x and y is :

If the point (x,y) is equidistant from the points (2,-1) and (-3,4) , then show that , y=x+2 .