[6278976:" If "theta" is the angle between the "],[" diagonals of a parallelogram "ABCD" whose "],[" vertices are "A(0,2),B(2,-1),C(4,0)" and "],[D(2,3)." Show that "tan theta=2]

Find the angle between the diagonals of parallelogram ABCD whose vertices are A (0, 2), B (2, - 1), C (4, 0) and D (2, 3).

The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) and C(8,3) is (a) (0,1) (b) (0,-1) (c) (-1,0) (d) (1,0)

If theta is the angle between the curves xy = 2 and x^(2)+4y = 0 then tan theta =

If vertices of a parallelogram are respectively (0,0), (1,0) ,(2,2) and (1,2) then angle between diagonals is

If vertices of a parallelogram are respectively (0,0), (1,0) ,(2,2) and (1,2) then angle between diagonals is

If theta is the angle between the lines joining the points A(0, 0) and B(2, 3), and the points C(2,-2) and D(3,5), show that tan theta=(11)/(23)

The vertices of a reactangle ABCD are A (-1, 0) B (2,0), C (a,b) and D(-1, 4). Then the length of the diagonal AC is

Show that the points A(1,2),B(4,3),C(1,0) and D(-2,-1) are the vertices of a parallelogram.

Show that the points A(1,2),B(4,3),C(1,0) and D(-2,-1) are the vertices of a parallelogram.

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2