(a+b+c)/(a^(-1)b^(-1)+b^(-1)c^(-1)+c^(-1)a^(-1))=abc

( Prove that: )/(a^(-1)b^(-1)+b^(-1)c^(-1)+c^(-1)a^(-1))=abc

Prove that: (a+b+c)/(a^(-1)\ b^(-1)+b^(-1)\ c^(-1)+c^(-1)a^(-1))=a b c

If abc=1, then ((1)/(1+a+b^(-1))+(1)/(1+b+c^(-1))+(1)/(1+c+a^(-1)))=? a.0 b.ab c.1 d.(1)/(ab)

If abc=1, show that (1)/(1+a+b^(-1))+(1)/(1+b+c^(-1))+(1)/(1+c+a^(-1))=1

If abc=1, show that (1)/(1+a+b^(-1))+(1)/(1+b+c)+(1)/(1+c+a^(-1))=1

if abc =2 then the value of (1)/(1+a+2b^(-1))+(1)/(1+(b)/(2)+c^(-1))+(1)/(1+a^(-1)+c)=

Prove that 1/(a(a-b)(a-c))+1/(b(b-c)(b-a))+1/(c(c-a)(c-b))=1/(abc)

If a,b,c are positive real numbers,then sqrt(a^(-1)b)x sqrt(b^(-1)c)x sqrt(c^(-1)a) is equal to: 1 (b) abc(c)sqrt(abc)(d)(1)/(abc)

The area of triangle formed by the vertices (a, 1/a), (b, 1/b), (c, 1/c) is (a) |((a+b)(b+c)(c+a))/(2abc)| (b) |((a-b)(b-c)(c-a))/(2abc)| (c) |((a-(1)/(a))(b-(1)/(b))(c-(1)/(c )))/(2)| (d) |((a-1)(b-1)(c-1))/(2abc)|