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[" 6."9^(1/3),9^(1/9),9^(1/27),..." upto...

[" 6."9^(1/3),9^(1/9),9^(1/27),..." upto the infinite then last value is "],[[" (a) "1," (b) "0," (c) "3," (d) None "],[" 7."log_(16)512" is equal to ",," a "]]

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The value of 9^(1/3), 9^(1/9).9^(1/27)…………..upto infty is:

Prove that 9^(1//3)xx9^(1//9)xx9^(1//27)xx...oo=3 .

9,3,1,(1)/(3),(1)/(9),"…."

9,3,1,(1)/(3),(1)/(9),"…."

9,3,1,(1)/(3),(1)/(9),"…."

9,3,1,(1)/(3),(1)/(9),"…."

If log27=1.431, then the value of log 9 is

If S=1+4/3+9/9+(16)/(27)+oo, then find the value of [S] (where [.] is G.I.F.)

If S=1+4/3+9/9+(16)/(27)+oo, then find the value of [S] (where [.] is G.I.F.)

When simplified (-1/(27))^(-2/3) is (a) 9 (b) -9 (c) 1/9 (d) -1/9