[" Question "4:],[y=e^(2x)(a+bx)]

Find the differential equation satisfying y=e^(2x)(a+ bx ) ,a and b are arbitrary constants.

The differential equation for y=e^(x)(a+bx) is

Verify that the function y=c_(1)e^(ax)cos(bx)+c_(2)e^(ax)sin(bx)

Form differential equation for y=e^(x)(a+bx+x^(2)) A) y_(2)-2y_(1)+y=2e^(x) B) y_(2)+2y_(1)-y=2e^(x) C) y_(2)-2y_(1)-y=2e^(x) D) y_(1)-2y_(2)+y=2e^(x)

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.y=e^(2x)(a+bx)

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b: y = e^(2x) (a + bx)

Verify that the function y=C_(1)e^(x)cos bx+C_(2)e^(ax)sin bx,C_(1),C_(2) are arbitrary constants is a solution of the differential equation: (d^(2)y)/(dx)-2a(dy)/(dx)+(a^(2)+b^(2))y=0

Find derivative of y=e^(ax)sin bx

Find derivative of y=e^(ax)cos bx

The solution of the differential equation (dy)/(dx) = (3e^(2x) + 3e^(4x) )/( e^(x) + e^(-x) ) is a) y= e^(3x) + C b) y=2e^(2x) + C c) y= e^(x) + C d) y= e^(4x) + C