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For the given series of reaction, 4NH(...

For the given series of reaction,
`4NH_(3)(g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O(l)`
`2NO(g) + O_(2)(g) rarr 2NO(g) +O_(2)(g) rarr 2NO_(2)(g)`
To obtain maximum mass of `NO_(2)` from a given mass of a mixture of `NH_(3)` and `O_(2)` the ratio of mass of `NH_(3)` ot `O_(2)` should be:

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For the given series of reaction, 4NH_(3)(g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O(l) 2NO(g) + O_(2)(g) rarr 2NO(g) +O_(2)(g) rarr 2NO_(2)(g) Total volume of O_(2) used if 20 ml NH_(3) is mixed with 100 ml O_(2) is :

To obtain maximum mass of NO_(2) from a given mass of a mxiture of NH_(3) and O_(2) , the ratio of mass of NH_(3) to O_(2) should be 2NH_(3)+(7)/(2)O_(2) rarr 2NO_(2)+3H_(2)O

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