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f(x)=(x-1)|(x-2)(x-3)|dot Then f decre...

`f(x)=(x-1)|(x-2)(x-3)|dot` Then `f` decreases in (a)`(2-1/(sqrt(3)),2)` (b) `(2,2+1/(sqrt(3)))` (c)`(2+1/(sqrt(3)),4)` (d) `(3,oo)`

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