The point `P(9/2,6)` lies on the parabola `y^(2)=4ax` then parameter of the point `P` is:

The point (8,4) lies inside the parabola y^(2) = 4ax If _

The line 4x+6y+9 =0 touches the parabola y^(2)=4ax at the point

The line 4x+6y+9 =0 touches the parabola y^(2)=4ax at the point

Let the normals at points A(4a, -4a) and B(9a, -6a) on the parabola y^(2)=4ax meet at the point P. The equation of the nornal from P on y^(2)=4ax (other than PA and PB) is

Let the normals at points A(4a, -4a) and B(9a, -6a) on the parabola y^(2)=4ax meet at the point P. The equation of the nornal from P on y^(2)=4ax (other than PA and PB) is

Let p be a point on the parabola y^(2)=4ax then the abscissa of p ,the ordinates of p and the latus rectum are in

Q is any point on the parabola y^(2) =4ax ,QN is the ordinate of Q and P is the mid-point of QN ,. Prove that the locus of p is a parabola whose latus rectum is one -fourth that of the given parabola.

Prove that BS is perpendicular to PS,where P lies on the parabola y^(2)=4ax and B is the point of intersection of tangent at P and directrix of the parabola.

P(t_(1)) and Q(t_(2)) are the point t_(1) and t_(2) on the parabola y^(2)=4ax. The normals at P and Q meet on the parabola.Show that the middle point PQ lies on the parabola y^(2)=2a(x+2a)