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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `B C_|_C D` . If `/_A D B""=theta,""B C""=""p""a n d""C D""=""q` , then AB is equal to (1) `(p^2+q^2costheta)/(pcostheta+qsintheta)` (2) `(p^2+q^2)/(p^2costheta+q^2sintheta)` (3) `((p^2+q^2)sintheta)/((pcostheta+qsintheta)^2)` (4) `((p^2+q^2)sintheta)/(pcostheta+qsintheta)`

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To solve the problem, we need to find the length of side AB in trapezium ABCD, given that AB is parallel to CD, BC is perpendicular to CD, and we have the angles and lengths specified. ### Step-by-step Solution: 1. **Understanding the trapezium**: - We have a trapezium ABCD where AB || CD. - BC is perpendicular to CD, which means angle BCD = 90°. - Let BC = p, CD = q, and angle ADB = θ. ...
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