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The equation of the circle passing th...

The equation of the circle passing through the foci of the ellipse `(x^2)/(16)+(y^2)/9=1` , and having centre at (0, 3) is (1) `x^2+y^2-6y+7=0` (2) `x^2+y^2-6y-5=0` (3) `x^2+y^2-6y+5=0` (4) `x^2+y^2-6y-7=0`

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Coordinates for focia re (ae, 0) , (-ar, 0)
`:. e=sqrt(1-(9)/(16))rArre=(sqrt(7))/(4)`
Coordinates of foci are `(sqrt(7),0),(-sqrt(7),0)`

Radius ` R=sqrt(7+9)=4`
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