Given :
`C("diamond")+O_(2)rarrCO_(2),DeltaH=-395 kJ`
`C("graphite")+O_(2)rarrCO_(2),DeltaH=-393 kJ`
The enthalpy of formation of diamond from graphite is

C_("diamond")+O_(2)(g)rarrCO_(2)(g),DeltaH=-395 kJ ...... (i) C_("graphite")+O_(2)(g)rarrCO_(2)(g),DeltaH=-393.5KJ" "…(ii) The DeltaH , when diamond is formed from graphite, is

Given that C+O_(2)rarrCO_(2),DeltaH^(@)=-xKJ and 2CO+O_(2)rarr2CO_(2),DeltaH^(@)=-yKJ The enthalpy of formation of carbon monoxide will be

Given that C+O_(2)rarrCO_(2),DeltaH^(@)=-xKJ and 2CO+O_(2)rarr2CO_(2),DeltaH^(@)=-yKJ The enthalpy of formation of carbon monoxide will be

Given that C+O_(2)rarrCO_(2),DeltaH^(@)=-xKJ and 2CO+O_(2)rarr2CO_(2),DeltaH^(@)=-yKJ The enthalpy of formation of carbon monoxide will be

The enthalpy change for the following reactions are: C_("diamond")+O_(2(g)) rarr CO_(2(g))" "DeltaH=-395.3 KJ "mol"^(-1) C_("graphite")+O_(2(g)) rarr CO_(2(g)) " "DeltaH=-393.4 KJ "mol"^(-1) The enthalpy change for the transition C_("diamond")rarr C_("graphite") will be :

If C(s)+O_(2)(g)rarrCO_(2)(g),DeltaH=X and CO(g)+1//2O_(2)(g)rarrCO_(2)(g),DeltaH=Y , then the heat of formation of CO is