Particles of masses `1kg` and `3kg` are at `2i + 5j + 13k)m` and `(-6i + 4j - 2k)m` then instantaneous position of their centre of mass is

Particles of masses 1 kg and 3 kg at (2i+5j+13 k) m and (-6i+4j-2k)m then instantaneous position of their centre of mass is

Particles of masses 1 kg and 3 kg at (2i+5j+13 k) m and (-6i+4j-2k)m then instantaneous position of their centre of mass is

Particles of masses 1kg and 2kg are at (i+2j+3k) m and (-2i+4j+2k)m then instantaneous position of their centre of mass is

Particles of masses 1kg and 3kg are moving with the velocities (10i-7j-3k)ms^(-1) and (7i-9j+6k)ms^(-1) then the instantaneous velocity of their centre of mass is

Two bodies of mass 2 kg and 5 kg have position (1 m, 2 m, 1 m) and (3 m, 2 m, -1 m) respectively. The position vector of centre of mass is

Two particles of mass 1 kg and 3 kg have position vectors 2 hat i+ 3 hat j + 4 hat k and -2 hat i+ 3 hat j - 4 hat k respectively. The centre of mass has a position vector.

Two bodies of mass 1 kg and 3 kg have position vectors hat i+ 2 hat j + hat k and - 3 hat i- 2 hat j+ hat k , respectively. The centre of mass of this system has a position vector.