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Figure shows a cylindridcal tube with a ...

Figure shows a cylindridcal tube with a adibatic walls and fitted with an adiabatic separtor. The separator can be slid into the tube by an external mechanism. An ideal gas`(gamma=1.5)` is injected in the two sides at equal pressures and temperatures . The separator remains in equilibrium at the middel. It is now slid to a position where it divides the tube in the ratio 1:3 Find the ratio of the tempertures in the two parts of the vessel.

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Shows a cylindrical tube with adiabatic walls and fittled with a diathermic separetor. The separetor can be slid in the tube by and external mechanism. An ideal gas is injected into the two sides at equal pressures and equal temperatures. The separetor remaons in equilibrium at the middle. It is now slid to pisition where it devides the tube in the ratio of 1:3. Find the ratio of the pressures in the two parts of the vessel.

Shows a cylindrical tube with adiabatic walls and fittled with a diathermic separetor. The separetor can be slid in the tube by and external mechanism. An ideal gas is injected into the two sides at equal pressures and equal temperatures. The separetor remaons in equilibrium at the middle. It is now slid to pisition where it devides the tube in the ratio of 1:3. Find the ratio of the pressures in the two parts of the vessel.

Shows a cylindrical tube with adiabatic walls and fittled with a diathermic separetor. The separetor can be slid in the tube by and external mechanism. An ideal gas is injected into the two sides at equal pressures and equal temperatures. The separetor remaons in equilibrium at the middle. It is mow slid to pisition where it devides the tube in the ratio of 1:3. Find the ratio of the pressures in the two parts of the vessel.

An adiabatic cylindrical tube is fitted with an adiabatic separator as shown in figure. Initial separator is in equilibrium and divides a tube in two equal parts. The seperator can be slide into the tube by an extermal mechanism. An ideal gas (gamma = 1.5) is injected in the two slides at equal pressure and temperature. Now separator is slid to a piston where it divides the tube in the ratio 7 :3 The ratio of the temperature in the two parts of the vessel is sqrt(n) : sqrt(7) find n .

An adiabatic cylindrical tube is fitted with an adiabatic separator as shown in figure. Initial separator is in equilibrium and divides a tube in two equal parts. The seperator can be slide into the tube by an extermal mechanism. An ideal gas (gamma = 1.5) is injected in the two slides at equal pressure and temperature. Now separator is slid to a piston where it divides the tube in the ratio 7 :3 The ratio of the temperature in the two parts of the vessel is sqrt(n) : sqrt(7) find n .

Figure shows an adiabatic cylindrical tube of volume (V_0) divided in two parts by a frictionless adibatic separator . Initially, the separator is kept in the middle, an ideal gas at pressure (p_1) and the temperatures (T_1) is injected into the left part and the another ideal gas at pressures (P_2) and temperature (T_2) is injected into the right part. (C_p / C_v = gamma) is the same for both the gases. The separator is slid slowly and is released at a position where it can stay in equilibrium. Find (a) the volumes of the parts, (b) the heat given to the gas in the left part and (c) the final common pressure of the gases.

Figure shows an adiabatic cylindrical tube of volume (V_0) divided in two parts by a frictionless adiabatic separator . Initially, the separator is kept in the middle, an ideal gas at pressure (P_1) and the temperatures (T_1) is injected into the left part and the another ideal gas at pressures (P_2) and temperature (T_2) is injected into the right part. (C_p / C_v = gamma) is the same for both the gases. The separator is slid slowly and is released at a position where it can stay in equilibrium. Find (a) the volumes of the parts, (b) the heat given to the gas in the left part and (c) the final common pressure of the gases.

In given figure, an adiabatic cylindrical tube of volume 2V_(0) is divided in two equal parts by a frictionless adiabatic separator. An ideal gas in left side of a tube having pressure P_(1) and temperature T_(1) where as in the right side having pressure P_(2) and temperature T_(2).C_(p)//C_(v) =gamma is the same for both the gases. The separator is slid slowly and is released at a position where it can stay in equilibrium. Find (a) the final volumes of the two parts (b) the heat given to the gas in the left part and (c) the final common pressure of the gases,

In given figure, an adiabatic cylindrical tube of volume 2V_(0) is divided in two equal parts by a frictionless adiabatic separator. An ideal gas in left side of a tube having pressure P_(1) and temperature T_(1) where as in the right side having pressure P_(2) and temperature T_(2).C_(p)//C_(v) =gamma is the same for both the gases. The separator is slid slowly and is released at a position where it can stay in equilibrium. Find (a) the final volumes of the two parts (b) the heat given to the gas in the left part and (c) the final common pressure of the gases,

In given figure, an adiabatic cylindrical tube of volume 2V_(0) is divided in two equal parts by a frictionless adiabatic separator. An ideal gas in left side of a tube having pressure P_(1) and temperature T_(1) where as in the right side having pressure P_(2) and temperature T_(2).C_(p)//C_(v) =gamma is the same for both the gases. The separator is slid slowly and is released at a position where it can stay in equilibrium. Find (a) the final volumes of the two parts (b) the heat given to the gas in the left part and (c) the final common pressure of the gases,