Solve : Decide the are quadratic equation ?
`m^3-5m^2+4=0`

Answer

To determine whether the given equation \( m^3 - 5m^2 + 4 = 0 \) is a quadratic equation, we need to analyze the highest power of the variable \( m \).

### Step-by-Step Solution:

1. **Identify the given equation**:
The equation we need to analyze is:
\[ m^3 - 5m^2 + 4 = 0 \]

2. **Determine the highest power of the variable**:
In the equation, the terms are:
- \( m^3 \) (which has a power of 3)
- \( -5m^2 \) (which has a power of 2)
- \( 4 \) (which is a constant term with a power of 0)

The highest power of \( m \) in this equation is 3.

3. **Define a quadratic equation**:
A quadratic equation is defined as an equation of the form:
\[ ax^2 + bx + c = 0 \]
where \( a \), \( b \), and \( c \) are constants, and the highest power of the variable (in this case, \( x \)) is 2.

4. **Compare the highest power**:
Since the highest power of \( m \) in our equation is 3, and not 2, it does not meet the criteria for being a quadratic equation.

5. **Conclusion**:
Therefore, the equation \( m^3 - 5m^2 + 4 = 0 \) is **not** a quadratic equation.