There are six cards in a box, each bearing a number from 0 to 5 . Find the probability of each of the following events, that a card drawn shows,
i. a natural number.
ii. a number less than 1.
iii. a whole number .
iv. a number greater than 5.

Answer

`therefore P(A) = (n(A))/(n(S))= (5)/(6)` , `therefore P(B) = (n(B))/(n(S)) = (1)/(6)` , ` therefore P(C) = (n(C))/(n(S)) = (6)/(6) = 1` , `therefore P(D) = (n(D))/(n(S)) = (0)/(6) = 0`