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Six years before, the age of mother was ...

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.

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The age of father 10 years ago was thrice the age of his son.10 years hence father's age will be twice that of his son.Find the ratio of their present ages.

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Knowledge Check

  • The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

    A
    `5:2`
    B
    `7:3`
    C
    `9:2`
    D
    `13:4`
  • The age of a mother 10 years ago was thrice the age of her son. 10 years hence, the mother's age will be twice that of 9 her son. The ratio of their present ages is :

    A
    `12:5`
    B
    `6:1`
    C
    `7:3`
    D
    `4:2`
  • The age of a father 10 years ago was thrice the age of hisson. Ten years hence, the father’s age will be twice that of his son. The ratio of their present ages is

    A
    8:5
    B
    7:3
    C
    5:2
    D
    9:5
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    Four years ago, age of a person was 4 times that of his son. Six years later, the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

    The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

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