Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

The age of a mother 10 years ago was thrice the age of her son. 10 years hence, the mother's age will be twice that of 9 her son. The ratio of their present ages is :

The age of father 10 years ago was thrice the age of his son.10 years hence father's age will be twice that of his son.Find the ratio of their present ages.

Mrs. Mehra has two sons, one being exactly one year older than the other. At present, her age is equal to the sum of squares of ages of her sons. If 4 years hence her age becomes five times the age of the elder son then find the present ages of her sons.

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages.

Four years ago, age of a person was 4 times that of his son. Six years later, the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

The age of father is equal to the square of the age of his son. The sum of the age of the father and five times the age of the son is 66 years. Find their ages.

A man is 24 years older than his son. After two years, his age will be twice the age of his son. The present age of the son is: