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From the top of a building , an observer...

From the top of a building , an observer is looking at a scooter parked at some distance away , makes an angle of depression of `30^(@)` . If the height of the building is 40 m , find how far the scooter is from the building. `(sqrt(3) = 1.73)`

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The correct Answer is:
69.20m
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UNIQUE PUBLICATION-TRIGONOMETRY-UNIQUE PRACTICE SESSION
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  3. त्रिकोणमितीय सर्वसमिकाओं को सिद्ध करो : (1)/(cosec A- cot A )-(1)/(s...

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  4. Prove that sqrt((1+sintheta)/(1-sintheta))=sectheta+tantheta

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  5. The length of the shadow of a tower standing on level plane is foun...

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  6. A circus artist is climbing from the ground along a rope stretched ...

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  7. An observer at a distance of 10 m from a tree looks at the top of the ...

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  10. Prove that : (tan theta)/(sec theta -1) + (tan theta)/(sec theta + 1...

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  11. Prove that (1+tan theta )^2 + (1+cot theta)^2 = (sec theta + cosec t...

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  12. Prove that (1 + 1/(tan^2A)) (1 + 1/(cot^2A)) = 1/(sin^2 A - sin^4 A )

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  13. Prove that: (sectheta-1)/(sectheta+1)=((sintheta)/(1+costheta))^2

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  16. To find the width the river, a man observes the top of a tower on the ...

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  17. Eliminate theta if x=a cot theta -b cosec theta and y=acot theta+b cos...

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