`sin theta =cos square`

Complete the relation in ratios given below . (i) (sin theta)/(cos theta) = square (ii) sin theta = cos (90- square) (iii) cos theta = sin ( 90- square ) (iv) tan theta xx tan (90- theta) = square

The maximum area of the triangle formed by the points (0,0)*(a cos theta,b sin theta) and (a cos theta,-b sin theta) (in square units)

In the figure sin theta=square, tan theta =square

Prove cot theta+tan theta=(cosec theta)(sec theta) by completing the following activity: LHS =cot theta+tan theta =(cos theta)/(sin theta)+(square)/(cos theta) =(square +square)/(sin thetaxx co cos theta) =(square)/(sin thetaxx cos theta) =1/(square)xx1/(square) =cosec thetaxx sec theta =RHS :.cot theta+tan theta=cosec thetaxx sec theta

Simplify: cos theta[cos theta sin theta-sin theta cos theta]+sin theta[sin theta-cos theta cos theta sin theta]

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

If cos theta + sin theta =sqrt2 cos theta , then the value of (cos theta -sin theta)/(sin theta) is

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

(((cos theta+sin theta)^(4)-(cos theta-sin theta)^(4))/(sin theta cos theta))=?