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Express (1-i)^(3)(1+i) in the form of a+...

Express `(1-i)^(3)(1+i)` in the form of `a+ib`

Text Solution

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`(1-i)^(3)(1+i)=(1-i)^(2)(1-i)(1+i)`
`=(1+i^(2)-2i)(1^(2)-i^(2))`
`=0-4i=0+i(-4)`
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