Home
Class 12
MATHS
Theorem: Let f(x)=ax^(2)+bx+c be a quadr...

Theorem: Let `f(x)=ax^(2)+bx+c` be a quadratic function.
If `a lt 0` then f(x) has maximum value at `x=(-b)/(2a)` and the maximum value `=(4ac-b^(2))/(4a)`

Text Solution

Verified by Experts

The correct Answer is:
`=(4ac-b^(2))/(4a)`
Promotional Banner

Topper's Solved these Questions

  • QUADRATIC EXPRESSIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES|68 Videos

  • QUADRATIC EXPRESSIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Short Answer Questions|8 Videos

  • PROBABILITY

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE|13 Videos

  • QUESTION PAPER -2019

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Long Answer Type questions|7 Videos

Similar Questions

Explore conceptually related problems

Theorem : Let f(x)=ax^(2)+bx+c be a quadratic function. If a gt 0 then f(x) has minimum value at x =(-b)/(2a) and the minimum value = (4ac -b^(2))/(4a)

Theorem: Let f(x)=ax^(2)+bx+c be a quadratic function. If a gt0 then f(x) has minimum value at x=(-b)/(2a) and the minimum value =(4ac-b^(2))/(4a) .

the maximum value of c+2bx - x^2 is

Find the maximum value of f(x) = x^(3)(2-x)^(4)

If a quadratic function in x has the value 9 when x=1 and has maximum value 10 when x=2 then the function is

The maximum value of f(x)=(x-2)^(2)(x-3) is

A quadratic function in x has the value 9 when x = 1 and has a maximum value 10 when x = 2. Find the function.

For what values of k, f(x) = x-(k)/(x) has a maximum value at x = -2.