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If alpha ,beta,gamma are the roots of x...

If `alpha ,beta,gamma` are the roots of `x^3+px^2+qx+r=0` , then form the cubic equation whose roots are `alpha(beta+gamma),beta(gamma+alpha),gamma(alpha+beta)`

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The correct Answer is:
`therefore x^3-2qx^2+(q^2+pr)x-r(pq-r)=0`
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