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Prove that 6^(2n)-35n-1 is divisible by ...

Prove that `6^(2n)-35n-1` is divisible by 1225 for all natural numbers of n.

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VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-BINOMIAL THEOREM-TETUAL EXERCISES (EXERCISE - 6(c)) I.
  1. Prove that 6^(2n)-35n-1 is divisible by 1225 for all natural numbers o...

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  2. Find an approximate value of the following corrected to 4 decimal pla...

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  3. Find an approximate value of the following corrected to 4 decimal pla...

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  4. Find an approximate value of the following corrected to 4 decimal pla...

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  5. Find an approximate value of the following corrected to 4 decimal pla...

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  6. Find an approximate value of the following corrected to 4 decimal pla...

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  7. Find an approximate value of the following corrected to 4 decimal pla...

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  8. If |x| is so small that x^(2) and higher powers of x may be neglected ...

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  9. If |x| is so small that x^(2) and higher powers of x may be neglected ...

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  10. If |x| is so small that x^(2) and higher powers of x may be neglected ...

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  11. If |x| is so small that x^(2) and higher powers of x may be neglected ...

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  12. If |x| is so small that x^(2) and higher powers of x may be neglected ...

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  13. Suppose s and t are positive and t is very small when compared to s. T...

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  14. Suppose p, q are positive and p is very small when compared to q. The...

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  15. By neglecting x^(4) and higher powers of x, find an approximate value ...

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  16. Expand 3sqrt(3) in increasing powers of (2)/(3).

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