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If the coefficients of x^(9),x^(10),x^(1...

If the coefficients of `x^(9),x^(10),x^(11)` in expansion of `(1+x)^(n)` are in A.P., the prove that `n^(2)-41n+398=0`.

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Knowledge Check

  • If the coefficients of x^9, x^10, x^11 in the expansion of (1+x)^n are in arithmetic progression then n^2=41n=

    A
    398
    B
    298
    C
    `-398`
    D
    198

  • If the coefficients of x ^(9), x ^( 10) , x ^ ( 11 ) in the expansion of (1 + x ) ^n are in arithmetic progression then n^ 2 - 41 n =

    A
    `398`
    B
    `298`
    C
    `-398`
    D
    `198`

  • If the coefficients of 2nd, 3rd, and 4th term in the expansion of (1+x)^(2n) are in A.P., then

    A
    `2n^2+9n+7=0`
    B
    `2n^2-9n+7=0`
    C
    `2n^2 +9n - 7 =0`
    D
    `2n^2 +9n -7 =0`

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