There is a uniform electric field in the XOY plane represented by `(40hat(j)+30hat(j))Vm^(-1)`. If the electric potential at the origin is 200 V, the electric potential at the point with coordinates (2m,1m) is

Explanation

Given uniform Electric field intensity.
`vec(E)=(40hat(i)+30hat(j))Vm^(-1)`
Position vector `d vec(r) =(2hat(i)+Ihat(j))m`
We know that ,

`d V=-vec(E).dvec(r)=-(40hat(i)+30hat(j)).(2hat(i)+hat(j))`
`V_(p)-V_(0)=-(80+30)=-110`Volt
`V_(p)=V_(0)-110=(200-110)"Volt"=90"Volt"`
`therefore` Potential at point `P,V_(p)=90"Volt"`.