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ABC is an equilateral triangle of side 2...

ABC is an equilateral triangle of side 2m. There is a uniform electric field of intensity 100V/m in the plane of the triangle and parallel to BC as shown. If the electric potential at A is 200V, then the electric potentials at B and C.

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Given length of side of an equilateral triangle a = 2m
E = 100 V/m' `V_(A) = 200 V`
Let D be the mid point between B and C
Potential at `D = V_(D) = 200 V`

From fig. `V_(B) - V_(D) = Ed`
`implies V_(B) - 200 = 100 xx 1`
`:.` potential at B, `V_(B) = 300 V`
And `V_(D) - V_(C) = Ed`
`200 - V_(C ) = 100 xx 1`
`:.` potential at `C, V_(c ) = 100 V`
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