There is a uniform electric field in the XOY plane represented by `(40hat(j)+30hat(j))Vm^(-1)`. If the electric potential at the origin is 200 V, the electric potential at the point with coordinates (2m,1m) is

Explanation

Given, uniform Electric field intensity.
`vec(E)=(40hat(i)+30hat(j))Vm^(-1)`
Electric potentila at the origin `=200V`
Position vector `d vec(r)=(2hat(i)+1hat(j))m`
We know that ,

`d V=-vecE*D=d vecr =-(40 hati + 30 hatj) * ( 2 hati + hatj)`
`V_(p)-V_(o)=-(80 + 30)=-110` Volt
`V_(P)=V_(o)-110=(200-110)Volt =90 Volt `
`:.` Potential at point ` P,V_(p)=90`Volt