Equations of the lines passing through a point `(x_1,y_1)` and making an angle `alpha` with the line y=mx+c is written as `y-y_1=(m+-tan alpha)/(1+-mtan alpha)(x-x_1)`

Equations of the lines passing through a point (x_(1),y_(1)) and making an angle alpha with the line y=mx+c is written as y-y_(1)=(m+-tan alpha)/(1+-m tan alpha)(x-x_(1))

Statement - 1 : Equations (2 pm sqrt3) x - y = 1 pm 2sqrt3 represent two sides of an equilateral triangle having one vertex (2 , 3) and x + y - 2 = 0 as the opposite side . Statement - 2 : The equation of the lines passing through (x_(1) , y_(1)) and making constant angle alpha with the line y = mx + c are given by y - y_(1) = (m pm tan alpha)/( 1 pm tan alpha) ( x - x_(1))

Statement - 1 : Equations (2 pm sqrt3) x - y = 1 pm 2sqrt3 represent two sides of an equilateral triangle having one vertex (2 , 3) and x + y - 2 = 0 as the opposite side . Statement - 2 : The equation of the lines passing through (x_(1) , y_(1)) and making constant angle alpha with the line y = mx + c are given by y - y_(1) = (m pm tan alpha)/( 1 pm tan alpha) ( x - x_(1))

The equations of the lines passing through (-10, 4) and making an angle tan^(-1)2 with the line 2y=x-10 are

The equation of straight line passing through the origin and making an angle alpha with the straight line x+y=0 is

The equation of the line passing through (1,1) and makes an angle pi//4 with the line 2x-y+7=0 is

The equation of the line passing through (1, 1) and makes an angle pi//4 with the line 2x-y+7=0 is

The equation to the striaght lines passing through the origin and making an angle alpha with straight line y+x=0 are given by

The equation to the striaght lines passing through the origin and making an angle alpha with straight line y+x=0 are given by

Find the equation of the straight lines passing through the origin making an angle alpha with the straight line y=mx+c .