If nitrogen gas molecule goes straight up with its rms speed at `0^@ C` from the surface of the earth and there are no collisions with other molecules, then it will rise to an approximate height of.

The velocity of a nitrogen molecule on the earth surface is equal to its rms speed at 0^@C IF the molecule moves straights upwards without any collisions with other molecules, determine the height up to which the molecule would rise. The mass of a nitrogen molecule m=4.65 times 10^-26 kg and k=1.38 times 10^-23 J.K^-1

A nitrogen molecule at the surface of earth happens to have 'rms' speed for that gas at 0^(@)C . If it were to go straight up without colliding with other molecules, how high would it rise? (Mass of nitrogen molecule, m=4.65xx10^(-26) kg,R=8.3J//mol//K )

A nitrogen molecules at teh surface of earth happens to have the rms speed for that gas at 0^(@) . If it were to go straight up without colliding with other molecules, how high would it rise? Mass of nitrogen molecules, m = 4.65 xx 10^(26)lg, k=1.38 xx 10^(-23)J "molecule"^(-1) K^(-1) .

A gas molecule at the surface of earth happens to have the rms speed for the gas at 0^(@)C . Suppose it went straight up without colliding with other molecules, how high it would rise? Mass of the molecule is 4.65 xx 10^(-26) kg . Boltzmann's constant = 1.38 xx 10^(-23) JK^(-1) .

If c_(0) and c denote the sound velocity and the rms velocity of the molecules in a gas, then

If c_(0) and c denote the sound velocity and the rms velocity of the molecules in a gas, then

If the rms speed of the nitrogen molecules of the gas at room temperature is 500 m/s, then the rms speed of the hydrogen molecules at the same temperature will be –