An experiment is performed to obtain the value of acceleration due to gravity g by using a simple pendulum of length L. In this experiment time for 100 oscillations is measured by using a watch of 1 second least count and the value is 90.0 seconds. The length L is measured by using a meter scale of least count 1 mm and the value is 20.0 cm. The error in the determination of g would be:

In a simple pendulum experiment for determination of acceleration due to gravity (g), time taken for 20 oscillation is measured by using a watch of 1 second least count. The mean value of time taken comes out to be 30 s. The length of pendulum is measured by using a meter scale of least count 1 mm and the value obtained is 55.0 cm. The percentage error in the determination of g is close to :

In a simple pendulum experiment for determination of acceleration due to gravity (g) , time taken for 20 oscillations is measure by using a watch of 1 second least count. The means value of time taken comes out to be 30s. The length pf pendulum is measured by using a meter scale of least count 1mm and the value obtined is 55.0 cm The percentage error in the determination of g is close to :

The length of a cylinder is measured as 5 cm using a vernier calipers of least count 0.1 mm. The percentage error is

The length of a cylinder is measured as 5 cm using a vernier calipers of least count 0.1 mm. The percentage error is

The length of a cyclinder is measured as 5 cm using a vernier calipers of least count 0.1 mm. The percentage error in the measured length is nearly

The length of an object was measured to be 30 cm by a linear scale of least count 0.1 cm. what is the % error?

A simple pendulam completes 20 oscillations in 25 S . The time is measured with a stop watch of least count 0.1 S . The error in the measurement is