Roots of the equation `(x^2-4x+3)+lamda(x^2-6x+8)=0` , `lamda in R` will be

Roots of the equation (x^(2)-4x+3)+lambda(x^(2)-6x+8)=0lambda in R will be

Roots of the quadratic equation (x^2-4x+3)+lamda(x^2-6x+8)=0,lamdainR will be

The equation (x^(2)-6x+8)+lambda (x^(2)-4x+3)=0, lambda in R has

Let alpha, beta be two real roots of the equation cot ^ 2 x - 2 lamda cot x + 3 = 0 , lamda in R . If cot ( alpha + beta ) = (1)/(2) , then value of lamda is :

Let alpha, beta be two real roots of the equation cot ^ 2 x - 2 lamda cot x + 3 = 0 , lamda in R . If cot ( alpha + beta ) = (1)/(2) , then value of lamda is :

Let alpha, beta be two real roots of the equation cot ^ 2 x - 2 lamda cot x + 3 = 0 , lamda in R . If cot ( alpha + beta ) = (1)/(2) , then value of lamda is :

alpha , beta are roots of the equation lamda (x^2-x)+x+5=0 If lamda_2 are the two values of lamda for which the roots alpha , beta are connceted by the relation ( alpha ) /( beta ) +( beta) /( alpha )=4 , then the value of ( lamda _1)/( lamda _2) +(lamda _2)/( lamda_1) is

Let lamdane 0 be in R. If alpha and beta are the roots of the equation x^(2) - x + 2lamda = 0 , and alpha and gamma are the roots of the equation 3x^2 - 10x + 27lamda = 0 , then (betagamma)/lamda is equal to __________

If alpha, beta are the roots fo the equation lamda(x^(2)-x)+x+5=0 . If lamda_(1) and lamda_(2) are two values of lamda for which the roots alpha, beta are related by (alpha)/(beta)+(beta)/(alpha)=4/5 find the value of (lamda_(1))/(lamda_(2))+(lamda_(2))/(lamda_(1))