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If g is the inverse of a function f and `f'(x) = 1/(1+x^(5))`, then g'(x) is equal to

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`g(f(x)) = x`
differentitate wrt x
`g'(f(x))*f'(x) = 1`
`g'(f(x)) = 1/(f'(x)) = 1 + x^5`
`g'((f(x))/(g(x))) = 1 + x^5`
`g`(f(g(x))) = 1 + (g(x))^5`
`g'(x) = 1 + (g(x))^5`
Answer
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