2n boys are randomly divided into two subgroups containing n boys each. The probability that the two tallest boys are in different groups is

2n boys are randomly divided into two subgroups containint n boys each. The probability that the two tallest boys are in different groups is a. n//(2n-1) b. (n-1)//(2n-1) c. (n-1)//4n^2 d. none of these

2n boys are randomly divided into two subgroups containint n boys each. The probability that eh two tallest boys are in different groups is n//(2n-1) b. (n-1)//(2n-1) c. (n-1)//4n^2 d. none of these

40 boys of a class are divided into two equal group. Find the probability that the 2 tallest boys are in two different groups.

24 boys are divided randomly into two equal groups. The probability that two tallest boys are in the different groups is

If 15 boys of different ages are distributed into 3 groups of 4,5, and 6 boys randomly then the probability that three youngest boys are in different groups is

10 boys and 2 girls are divided into 3 groups of 4 each.The probability that the girls will be in different groups is

6 boys and 6 girls are randomly divided into two equal groups. Find the probability that each group contains same number of boys and girls.

The number of ways in which 10 boys can be divied into 2 groups of 5, such that two tallest boys are in two different groups, is equal to