Forces `3 O vec A , 5 O vec B ` act along OA and OB. If their resultant passes through C on AB, then

Forces 3O vec A , 5O vec B act along O A a n d O Bdot If their resultant passes through C on AB , then C is a a. mid point of AB b. C divides AB in the ratio 2:1 c. 3A C=5C B d. 2A C=3C B

Here is a ray vec(OA) . It starts at O and passes through the point A. It also passes through the point B. Can you also name it as vec(OB) ? Why? vec(OA) and vec(OB) are same here. Can we write vec(OA) as vec(AO) ? Why or why not? Draw five rays and write appropriate names for them. , What do the arrows on each of these rays show?

ABCD is a quadrilateral. Forces vec(AB), vec(CB), vec(CD) and vec(DA) act along its sides. What is their resultant ?

ABCD is a quadrilateral. Force vec(AB), vec(CB), vec(CD) and vec(DA) act along its sides. What is their resultant ?

Five forces vec A B , vec A C , vec A D , vec A E and vec A F act at the vertex of a regular hexagon A B C D E Fdot Prove that the resultant is 6 vec A O , where O is the centre of heaagon.

Five forces vec A B , vec A C , vec A D , vec A E and vec A F act at the vertex of a regular hexagon A B C D E Fdot Prove that the resultant is 6 vec A O , where O is the centre of hexagon.

Five forces vec AB,vec AC,vec AD,vec AE and vec AF act at the vertex of a regular hexagon ABCDEF . Prove that the resultant is 6vec AO, where O is the centre of heaagon.

ABCD is a quadrilateral and O is point in its plane. Show that if vec OA+ vec OB+ vec OC+ vec OD= vec 0 , then O is the point of the interection of the lines joining the mid-points of the opposite sides of ABCD.

If the vector product of a constant vector vec OA with a variable vector vec OB in a fixed plane OAB be a constant vector,then the locus of B is a.a straight line perpendicular to vec OA b.a circle with centre O and radius equal to |vec OA| c.a straight line parallel to vec OA d.none of these

If 2 vec A C = 3 vec C B , then prove that 2 vec O A =3 vec C B then prove that 2 vec O A + 3 vec O B =5 vec O C where O is the origin.