A circle with centre P is inscribed in the ` Delta ABC` Side AB, side BC and side A C touch the circle at points L,M and N respectively . Prove that :
` A (DeltaABC ) = 1/2 (AB +BC + AC) xxr`

A circle with centre P is inscribed in the triangle ABC. Side AB, side BC and side AC touch the circle at points L,M and N respectively. Radius of the circle is r. Prove that: A( triangle ABC)=(1)/(2)(AB+BC+AC)xxr .

In Fig.2, a quadrilateral ABCD is drawn to circumscribe a circle, with centre O, in such a way that the sides AB, BC, CD and DA touch the circle at the points P, Q, R and S respectively. Prove that AB + CD = BC + DA.

In Fig.2, a quadrilateral ABCD is drawn to circumscribe a circle, with centre O, in such a way that the sides AB, BC, CD and DA touch the circle at the points P, Q, R and S respectively. Prove that AB + CD = BC + DA.

The incircle of an isosceles triangle ABC, in which AB = AC, touches the sides BC, CA and AB at D, E and F respectively . Prove that BD = DC.

In the given figure the sides AB, BE and CA of triangle ABC touch a circle with centre O and radius r at P,Q and R respectively. Prove that : (i) AB+CQ=AC+BQ

The sides AB,BC and AC of a triangle ABC touch a circle with centre O and radius r at P Q,and R respectively.

A circle is touching the side BC of DeltaABC at P and touching AB and AC extended at Q and R respectively. Prove that, AQ=1/2 (permeter of DeltaABC) .

A circle touches the side BC of DeltaABC at P and touches AB and AC produced at Q and R respectively. Prove that AQ=1/2(Perimeter of DeltaABC).

A circle is touching the side BC of Delta ABC at P and touching AB and AC produced at Q and R respectively Prove that AQ=(1)/(2) (Perimeter of Delta ABC)