The switch is closed at `t = 0`. The time after which the rate of dissipation for energy in the resistor is equal to rate at which energy is being stored in the inductor is : (A) `ln2` (B) `(1)/(2) ln^(2)` (C) `(1)/(4) ln^(2)` (D) `2ln2`

The switch is closed at t=0. Find time after which voltage across capacitor becomes 50 V. (take ln 2 = 0.6)

Consider the RL circuit in Fig. When the switch is closed in position 1 and opens in position 2 , electrical work must be performed on the inductor and on the resistor. The energy stored in the inductor is for the resistor energy appears as heat. a. What is the ratio of P_(L)//P_(R ) of the rate at which energy is stored in the inductor to the rate at which energy is dissipated in the resistor? b. Express the ratio P_(L)//P_(R ) as a function of time. c. If the time constant of circuit is t , what is the time at which P_(L) = P_(R ) ?

Consider the RL circuit in Fig. When the switch is closed in position 1 and opens in position 2 , electrical work must be performed on the inductor and on the resistor. The energy stored in the inductor is for the resistor energy appears as heat. a. What is the ratio of P_(L)//P_(R ) of the rate at which energy is stored in the inductor to the rate at which energy is dissipated in the resistor? b. Express the ratio P_(L)//P_(R ) as a function of time. c. If the time constant of circuit is t , what is the time at which P_(L) = P_(R ) ?

The value of int _(2) ^(4) ((log t )/( t)) dt is a) 1/2 (log 2) ^(2) b) 3/2 (log 2) ^(2) c) (log 2) ^(2) d) 5/2 (log 2) ^(2)

The graph between log t_(1//2) and log a at a given temperature is Rate of this reaction will …….with passage of time

The graph between log t_(1//2) and log a at a given temperature is Rate of this reaction will …….with passage of time

int_2^4((log)_x2-(((log)_2 2)^2)/(ln2))dx= 0 (b) 1 (c) 2 (d) 4