In an isothermal expansion of a gaseous sample the correct relation is (consider `w`(work) with sign according to new `IUPAC` convention)
[The reversible and irreversible processes are carried out between same initial and final states]

In an isothermical expansion of a gaseous sample the correct relation is (consider w (work) with sign according to IUPAC convention) [The reversible and irreversible procss are carried out between same initial and final states.]

Statement -1: The magnitude of the work involved in an isothermal expansion is greater than that involved in an adiabatic expansion. Statement -2: P-v curve (P on y -axis and V on X-axis) decrease more rapidly for reversible adiabatic expansion compared to reversible isothermal expansion starting from same initial state.

This question has Statement I and Statement II. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement-I : The magnitude of the work involved in an isothermal expansion is greater than that involved in an adiabatic expansion. Statement-II : P-V curve (P on y-axis and V on x-axis) decrease more rapidly for reversible adiabatic expansion compared to reversible isothermal expansion starting from same initial state.

Staetement -1: The magniyude of the work involed in an isothermal expansion is greater than that involved in an adiabatic expansion. Statement -2: P-v cure (pon y -axas and V on X-axas) decrease more repidly for reversible asiabatic expansion compared to reversible isothermal expansion starting from same initial state.

Staetement -1: The magniyude of the work involed in an isothermal expansion is greater than that involved in an adiabatic expansion. Statement -2: P-v cure (pon y -axas and V on X-axas) decrease more repidly for reversible asiabatic expansion compared to reversible isothermal expansion starting from same initial state.

Four sample of ideal gas containig same moles and intially at same temperature and prcessure are subjected to four difference processes : (A) Isothermal reversible expansion (B) Isothermal irrversible expansion against final pressure (C ) Adiabatic reversible expansion (D) Adiabatic irreversible expansion against final pressure If in all the cases , final pressue is same then what will be the order of final temperture in the above cases.

A gaseous sample is generally allowed to do only expansion // compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion // compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V) , so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. If four identical samples of an ideal gas initially at similar state (P_(0),V_(0),T_(0)) are allowed to expand to double their volumes by four different process. I: by isothermal irreversible process II: by reversible process having equation P^(2)V= constant III. by reversible adiabatic process IV. by irreversible adiabatic expansion against constant external pressure. Then, in the graph shown in the final state is represented by four different points then, the correct match can be

A gaseous sample is generally allowed to do only expansion // compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion // compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V) , so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. If four identical samples of an ideal gas initially at similar state (P_(0),V_(0),T_(0)) are allowed to expand to double their volumes by four different process. I: by isothermal irreversible process II: by reversible process having equation P^(2)V= constant III. by reversible adiabatic process IV. by irreversible adiabatic expansion against constant external pressure. Then, in the graph shown in the final state is represented by four different points then, the correct match can be