A particle of mass m is projected at an angle with horizontal with kinetic energy E. the potential energy at the top of its trajectory is `E/2`. Find the range.

A particle m is projected at an angle with the horizontal with kinetic energy E. The potential energy at the top of its trajector is E/2. The range of the particle is (xE)/(mg) , then find the value of x is

A body projected at an angle theta to the horizontal with kinetic energy E_k . The potential energy at the highest point of the trajectory is

A body projected at an angle theta to the horizontal with kinetic energy E_k . The potential energy at the highest point of the trajectory is

A particle is projected at an angle of 60^(@) to the horizontal with a kinetic energy E. The kinetic energy at the highest point is

A particle is projected at 60 ^@ to the horizontal with kinetic energy K. Its kinetic energy at the highest point is :

A particle is projected at 60 ^@ to the horizontal with kinetic energy K. Its kinetic energy at the highest point is :

A particle is projected at 60^@ to the horizontal with energy E . The kinetic energy and potential energy at the highest point are

An object of mass m is projected at an angle 60^(@) (with horizontal axis) with a velocity v.Its kinetic energy at the peak of the trajectory is