यदि `tan A= x+1` और `tanB =x-1` हो, तब ` x^(2) tan(A-B)` का मान क्या है ?

Options

A. 1
B. x
C. 0
D. 2

Answer

d

Explanation

दिया है , `tan a = x+1 " "` …(i)
तथा ` tan B = x-1 " " `…(i)
अब , `x^(2) (A-B) =x^(2) ((tan A - tanB)/(1+tanA*tanB))`
` {x^(2) {(x+1)-(x-1))/(1+(x+1)*(x-1))}`
` = x^(2) (2/(1+x^(2)-1))=x^(2)*2/x^(2)=2`