यदि `int x^(2) "In" x dx=(x^(3))/(m) "In" x+(x^(2))/(n)+C` है, तो m और n के मान क्रमशः क्या है ?

Options

A. `1//3-1//9`
B. `3,-9`
C. `3,9`
D. `3,3`

Explanation

`int x^(2)In x dx= In x*(x^(3))/(3)-int (1)/(x)*(x^(3))/(3)dx`
`=(x^(3))/(3)In x- int (x^(2))/(3)dx`
`=(x^(3))/(3)In -(1)/(3)*(x^(3))/(3)+C=(x^(3))/(3)Inx-(x^(3))/(n)+C`
परन्तु `int x^(3)In x dx =(x^3))/(m) In x+(x^(3))/(n)+C`
`:,.m=4` तथा `n=-9` [ तुलना करने पर]