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A block of mass M is sliding down the pl...

A block of mass M is sliding down the plane. Coefficient of static friction is `mu_(s)` and kinetic friction is `mu_(k)`. Then friction force acting on the block is :

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A block of mass m rests on a rough horizontal plane having coefficient of kinetic friction mu_(k) and coefficient of static friction mu_(s) . The spring is in its natural, when a constant force of magnitude P=(5mu_(k)mg)/(4) starts acting on the block. The spring force F is a function of extension x as F=kx^(2).( Where k is spring constant ) (a) Comment on the relation between mu_(s) and mu_(k) for the motion to start. (b) Find the maximum extension in the spring ( Assume the force P is sufficient make the block move ) .

A block of mass m rests on a rough horizontal plane having coefficient of kinetic friction mu_(k) and coefficient of static friction mu_(s) . The spring is in its natural, when a constant force of magnitude P=(5mu_(k)mg)/(4) starts acting on the block. The spring force F is a function of extension x as F=kx^(2).( Where k is spring constant ) (a) Comment on the relation between mu_(s) and mu_(k) for the motion to start. (b) Find the maximum extension in the spring ( Assume the force P is sufficient make the block move ) .

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A force of 750 N is applied to a block of 100 kg to prevent it from sliding down an inclined plane of 30^(@) inclination. If coefficients of static and kinetic friction are 0.4 and 0.2, the frictional force acting is :