The vector `vecb = 3j + 4k` is to be written as the sum of a vector `vecb_1`, parallel to `veca = i + j`, and a vector `vecb_2`, perpendicular to `veca`, then `vecb_1`, equals

If the vector vecb = 3hati + 4hatk is written as the sum of a vector vecb_(1) parallel to veca = hati + hatj and a vector vecb_(2) , perpendicular to veca then vecb_(1) xx vecb_(2) is equal to:

If the vector vecb = 3hati + 4hatk is written as the sum of a vector vecb_(1) parallel to veca = hati + hatj and a vector vecb_(2) , perpendicular to veca then vecb_(1) xx vecb_(2) is equal to:

If vecb ne 0 , then every vector veca can be written in a unique manner as the sum of a vector veca_(p) parallel to vecb and a vector veca_(q) perpendicular to vecb . If veca is parallel to vecb then veca_(q) =0 and veca_(q)=veca . The vector veca_(p) is called the projection of veca on vecb and is denoted by proj vecb(veca) . Since proj vecb(veca) is parallel to vecb , it is a scalar multiple of the vector in the direction of vecb i.e., proj vecb(veca)=lambdavecUvecb" " (vecUvecb=(vecb)/(|vecb|)) The scalar lambda is called the componennt of veca in the direction of vecb and is denoted by comp vecb(veca) . In fact proj vecb(veca)=(veca.vecUvecb)vecUvecb and comp vecb(veca)=veca.vecUvecb . If veca=-2hatj+hatj+hatk and vecb=4hati-3hatj+hatk and veca=vec_(p)+veca_(q) then veca_(q) is equal to

If vecb ne 0 , then every vector veca can be written in a unique manner as the sum of a vector veca_(p) parallel to vecb and a vector veca_(q) perpendicular to vecb . If veca is parallel to vecb then veca_(q) =0 and veca_(q)=veca . The vector veca_(p) is called the projection of veca on vecb and is denoted by proj vecb(veca) . Since proj vecb(veca) is parallel to vecb , it is a scalar multiple of the vector in the direction of vecb i.e., proj vecb(veca)=lambdavecUvecb" " (vecUvecb=(vecb)/(|vecb|)) The scalar lambda is called the componennt of veca in the direction of vecb and is denoted by comp vecb(veca) . In fact proj vecb(veca)=(veca.vecUvecb)vecUvecb and comp vecb(veca)=veca.vecUvecb . If veca=-2hatj+hatj+hatk and vecb=4hati-3hatj+hatk then proj vecb(veca) is

If vecb ne 0 , then every vector veca can be written in a unique manner as the sum of a vector veca_(p) parallel to vecb and a vector veca_(q) perpendicular to vecb . If veca is parallel to vecb then veca_(q) =0 and veca_(q)=veca . The vector veca_(p) is called the projection of veca on vecb and is denoted by proj vecb(veca) . Since proj vecb(veca) is parallel to vecb , it is a scalar multiple of the vector in the direction of vecb i.e., proj vecb(veca)=lambdavecUvecb" " (vecUvecb=(vecb)/(|vecb|)) The scalar lambda is called the componennt of veca in the direction of vecb and is denoted by comp vecb(veca) . In fact proj vecb(veca)=(veca.vecUvecb)vecUvecb and comp vecb(veca)=veca.vecUvecb . If veca=-2hatj+hatj+hatk and vecb=4hati-3hatj+hatk then proj vecb(veca) is

If vecb ne 0 , then every vector veca can be written in a unique manner as the sum of a vector veca_(p) parallel to vecb and a vector veca_(q) perpendicular to vecb . If veca is parallel to vecb then veca_(q) =0 and veca_(q)=veca . The vector veca_(p) is called the projection of veca on vecb and is denoted by proj vecb(veca) . Since proj vecb(veca) is parallel to vecb , it is a scalar multiple of the vector in the direction of vecb i.e., proj vecb(veca)=lambdavecUvecb" " (vecUvecb=(vecb)/(|vecb|)) The scalar lambda is called the componennt of veca in the direction of vecb and is denoted by comp vecb(veca) . In fact proj vecb(veca)=(veca.vecUvecb)vecUvecb and comp vecb(veca)=veca.vecUvecb . If veca=-2hati+hatj+hatk and vecb=4hati-3hatj+hatk then proj vecb(veca) is

Find the projection vector of vecb=i+2j+k along the vector veca=2i+j+2k . Also write vecb as the sum of a vector along veca and a parpendicular to veca .

Let veca=2i+4j-5k , vecb=i+2j+3k . Then find a unit vector perpendicular to both veca and vecb .

vecA and vecB and vectors expressed as vecA = 2hati + hatj and vecB = hati - hatj Unit vector perpendicular to vecA and vecB is:

vecA and vecB and vectors expressed as vecA = 2hati + hatj and vecB = hati - hatj Unit vector perpendicular to vecA and vecB is: