If in the expansion of `(1+x)^n ,a ,b ,c` are three consecutive coefficients, then `n=` `(a c+a b+b c)/(b^2+a c)` b. `(2a c+a b+b c)/(b^2-a c)` c. `(a b+a c)/(b^2-a c)` d. none of these

If in the expansion of (1+x)^n ,a ,b ,c are three consecutive coefficients, then n= a. (a c+a b+b c)/(b^2+a c) b. (2a c+a b+b c)/(b^2-a c) c. (a b+a c)/(b^2-a c) d. none of these

If in the expansion of (1+x)^n ,a ,b ,c are three consecutive coefficients, then n= a. (a c+a b+b c)/(b^2+a c) b. (2a c+a b+b c)/(b^2-a c) c. (a b+a c)/(b^2-a c) d. none of these

If the coefficients of three successive terms in the expansion of (1+x)^(n) be a ,b and c respectively , then show that , n=(2ac+b(a+c))/(b^(2)-ac)and(a(b+c))/(b^(2)-ac)= no. of the terms has coefficients a .

If a,b,c be the three consecutive coefficients in the expansion of a power oif (1+x), prove that the index power is ( 2ac+b(a+c)/(b^2-ac))

If a,b,c,d are conseentive binomial coefficients of (1+x)^n then (a+b)/(a), (b+c)/(b), (c+d)/(c ) are is

If a,b,c,d are conseentive binomial coefficients of (1+x)^n then (a+b)/(a), (b+c)/(b), (c+d)/(c ) are is

If a ,\ b ,\ c are in proportion, then (a) a^2=b c (b) b^2=a c (c) c^2=a b (d) None of these

If a ,\ b ,\ &\ c are non zero real numbers, then |b^2c^2bcb+c c^2a^2cac+a a^2b^2aba+b| is equal to a. a^2b^2c^2(a+b+c) b. a b c(a+b+c)^2 c. zero d. none of these

If a+b+c=9 and a b+b c+c a=23 , then a^2+b^2+c^2=? (a)35 (b) 58 (c) 127 (d) none of these

Prove that =|1 1 1a b c b c+a^2a c+b^2a b+c^2|=2(a-b)(b-c)(c-a)