Two waves are given by`y_(1) = a sin (omega t - kx)` and `y_(2) = a cos (omega t - kx)`. The phase difference between the two waves is

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two sound waves are y = a sin (omegat - kx), y = a cos (omega - kx) . Phase difference between two waves is

y_1 =4sin( omega t + kx), y2 = -4 cos( omega t + kx), the phase difference is

if x = a sin (omegat + pi//6) and x' = a cos omega , t, then what is the phase difference between the two waves

Two waves are represented by y_(1)=a_(1)cos (omega t - kx) and y_(2)=a_(2)sin (omega t - kx + pi//3) Then the phase difference between them is-

Equations of a stationary and a travelling waves are as follows y_(1) = sin kx cos omega t and y_(2) = a sin ( omega t - kx) . The phase difference between two points x_(1) = pi//3k and x_(2) = 3 pi// 2k is phi_(1) in the standing wave (y_(1)) and is phi_(2) in the travelling wave (y_(2)) then ratio phi_(1)//phi_(2) is