The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid is 1.2 atm. When a non-volatile substance B is mixed in A, then its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent Its vapour pressure drops to 0.6 atm what is the mole fraction of B in solution ?