If S= 0!+ 1.1!+ 2.2!+.....+ n n!, then:

If a_1. a_2 ....... a_n are positive and (n - 1) s = a_1 + a_2 +.....+a_n then prove that (a_1 + a_2 +....+a_n)^n ge (n^2 - n)^n (s - a_1) (s - a_2)........(s - a_n)

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

S_(n) = (1+2+3+....+n)/( n) then S_(1)^(2) + S_(2)^(2) + S_(3)^(2) + ..... + S_(n)^(2) =

If sum of n termsof a sequende is S_n then its nth term t_n=S_n-S_(n-1) . This relation is vale for all ngt-1 provided S_0= 0. But if S_!=0 , then the relation is valid ony for nge2 and in hat cast t_1 can be obtained by the relation t_1=S_1. Also if nth term of a sequence t_1=S_n-S_(n-1) then sum of n term of the sequence can be obtained by putting n=1,2,3,.n and adding them. Thus sum_(n=1)^n t_n=S_n-S_0. if S_0=0, then sum_(n=1)^n t_n=S_n. On the basis of above information answer thefollowing questions:If nth term of a sequence is n/(1+n^2+n^4) then the sum of its first n terms is (A) (n^2+n)/(1+n+n^2) (B) (n^2-n)/(1+n+n^2) (C) (n^2+n)/(1-n+n^2) (D) (n^2+n)/(2(1+n+n^2)

If sum of n termsof a sequende is S_n then its nth term t_n=S_n-S_(n-1) . This relation is vale for all ngt-1 provided S_0= 0. But if S_!=0 , then the relation is valid ony for nge2 and in hat cast t_1 can be obtained by the relation t_1=S_1. Also if nth term of a sequence t_1=S_n-S_(n-1) then sum of n term of the sequence can be obtained by putting n=1,2,3,.n and adding them. Thus sum_(n=1)^n t_n=S_n-S_0. if S_0=0, then sum_(n=1)^n t_n=S_n. On the basis of above information answer thefollowing questions:If nth term of a sequence is n/(1+n^2+n^4) then the sum of its first n terms is (A) (n^2+n)/(1+n+n^2) (B) (n^2-n)/(1+n+n^2) (C) (n^2+n)/(1-n+n^2) (D) (n^2+n)/(2(1+n+n^2)

Consider the sequence of natural numbers S_0,S_1,S_2 ,... such that S_0 =3, S_1 = 3 and S_n = 3 + S_(n-1) S_(n-2) , then

Consider the sequence of natural numbers s_0,s_1,s_2 ,... such that s_0 =3, s_1 = 3 and s_n = 3 + s_(n-1) s_(n-2) , then

Consider the sequence of natural numbers s_0,s_1,s_2 ,... such that s_0 =3, s_1 = 3 and s_n = 3 + s_(n-1) s_(n-2) , then

If S_(n)=1+1/2+1/3+…+1/n(ninN) , then prove that S_(1)+S_(2)+..+S_((n-1))=(nS((n))-n)or(nS((n-1))-n+1)