A particle is projected from ground with some initial velocity making an angle of `45^(@)` with the horizontal.It reaches a height of `7.5 m` above the ground while it travels a horizontal distance of `10 m` from the point of projection.The initial speed of the projection is

A particle is projected from the ground with some initial velocity making an angle of 45^(@) with the horizontal. It reaches a height of 7.5 m above the ground while it travels a horzontal distance of 10 m from the point of projection . Find the initial speed of projection ( g = 10 m//s^(2) ) .

A particle is projected from the ground with velocity u making an angle theta with the horizontal. At half of its maximum heights,

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .