यदि
` u = sqrt(a^(2) cos^(2) theta + b^(2) sin^(2) theta) + sqrt( a^(2) sin^(2) theta + b^(2) cos^(2) theta)`
तब `u^(2)`के उच्चिष्ठ व निम्निष्ठ मानों में अंतर ज्ञात कीजिए ।

Let f(theta) = sqrt(a^2cos^2theta+b^2sin^2theta) + sqrt(a^2sin^2theta+b^2cos^2theta) Minimum value of [f(theta)]^2

Let f(theta) = sqrt(a^2cos^2theta+b^2sin^2theta) + sqrt(a^2sin^2theta+b^2cos^2theta) Maximum value of [f(theta)]^2

Show that the maximum and minimum values of sqrt(a^(2)cos^(2)theta + b^(2)sin^(2) theta) + sqrt(a^(2)sin^(2)theta + b^(2)cos^(2)theta) are sqrt(2(a^(2) +b^(2)) and a + b respectively.

u=sqrt(a^(2)cos^(2)theta+b^(2)sin^(2)theta)+sqrt(a^(2)sin^(2)theta+b^(2)cos^(2)theta) then the difference between maximum and minimum values of u^(2) is

If u = sqrt(a^(2) cos^(2)theta + b^(2) sin^(2)theta) + sqrt(a^(2) sin^(2)theta + b^(2) cos^(2)) , then the difference between the maximum and minimum values of u^(2) is given by :

If u=sqrt(a ^(2) cos ^(2) theta+b ^(2) sin ^(2) theta)+ sqrt( a^(2) sin ^(2) theta+b ^(2) cos ^(2) theta), then the difference between the maximum and minimum values of u^(2) is-